Question
At noon, a tank contained 6 in. of water. After several hours, it contained 3 in. of water. What is the percent decrease of water in the tank?
Question content area bottom
Part 1
The percent decrease of water in the tank is
enter your response here%.
Question content area bottom
Part 1
The percent decrease of water in the tank is
enter your response here%.
Answers
GPT-4o mini
To calculate the percent decrease in the amount of water in the tank, we can use the formula for percent change:
\[
\text{Percent Decrease} = \frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \times 100
\]
In this case:
- Original Value (amount of water at noon) = 6 inches
- New Value (amount of water after several hours) = 3 inches
Now plug these values into the formula:
\[
\text{Percent Decrease} = \frac{6 - 3}{6} \times 100 = \frac{3}{6} \times 100 = 0.5 \times 100 = 50\%
\]
So, the percent decrease of water in the tank is **50%**.
\[
\text{Percent Decrease} = \frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \times 100
\]
In this case:
- Original Value (amount of water at noon) = 6 inches
- New Value (amount of water after several hours) = 3 inches
Now plug these values into the formula:
\[
\text{Percent Decrease} = \frac{6 - 3}{6} \times 100 = \frac{3}{6} \times 100 = 0.5 \times 100 = 50\%
\]
So, the percent decrease of water in the tank is **50%**.