Question
Evaluate.
\[\left(-\dfrac{3}4\right)^2 = \]
\[\left(-\dfrac{3}4\right)^2 = \]
Answers
GPT-4o mini
To evaluate \(\left(-\dfrac{3}4\right)^2\), we follow the rule of squaring a number, which is to multiply the number by itself:
\[
\left(-\dfrac{3}4\right)^2 = \left(-\dfrac{3}4\right) \times \left(-\dfrac{3}4\right)
\]
When multiplying two negative numbers, the result is positive. Therefore:
\[
\left(-\dfrac{3}4\right) \times \left(-\dfrac{3}4\right) = \dfrac{3 \times 3}{4 \times 4}
\]
Calculating the numerator and the denominator gives:
\[
= \dfrac{9}{16}
\]
Thus, the final answer is:
\[
\left(-\dfrac{3}4\right)^2 = \dfrac{9}{16}
\]
\(\boxed{\dfrac{9}{16}}\)
\[
\left(-\dfrac{3}4\right)^2 = \left(-\dfrac{3}4\right) \times \left(-\dfrac{3}4\right)
\]
When multiplying two negative numbers, the result is positive. Therefore:
\[
\left(-\dfrac{3}4\right) \times \left(-\dfrac{3}4\right) = \dfrac{3 \times 3}{4 \times 4}
\]
Calculating the numerator and the denominator gives:
\[
= \dfrac{9}{16}
\]
Thus, the final answer is:
\[
\left(-\dfrac{3}4\right)^2 = \dfrac{9}{16}
\]
\(\boxed{\dfrac{9}{16}}\)