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3. What is the ka for a solution of choloracetic acid (C2H5ClO2) which has a pH of 1.52 in a 0.112M solution?

Please reply me as soon as possible sir

Thank you
George.
15 years ago

Answers

DrBob222
For simplicity, let's call cloroacetic acid HA.
Then HA ==> H^+ + A^-

Ka = (H^+)(A^-)/(HA)
Convert pH to (H^+) from pH = -log(H^+). (A^-) is the same. After equilibrium is attained, (HA) - 0.112-(H^+).
Solve for Ka.

15 years ago

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