Question
8. Derek is shooting a basketball and exerts a force on the ball, causing it to travel a certain distance. Which of the following best describes how the work he does on the ball is determined?
(1 point)
Responses
The work depends only on the distance the ball travels, regardless of the force exerted.
The work depends only on the distance the ball travels, regardless of the force exerted.
The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.
The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.
The work depends only on the force exerted by Derek, regardless of how far the ball travels.
The work depends only on the force exerted by Derek, regardless of how far the ball travels.
The work Derek does on the ball is unrelated to the force or distance, as it depends only on the ball’s weight.
(1 point)
Responses
The work depends only on the distance the ball travels, regardless of the force exerted.
The work depends only on the distance the ball travels, regardless of the force exerted.
The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.
The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.
The work depends only on the force exerted by Derek, regardless of how far the ball travels.
The work depends only on the force exerted by Derek, regardless of how far the ball travels.
The work Derek does on the ball is unrelated to the force or distance, as it depends only on the ball’s weight.
Answers
GPT-4o mini
The correct response is:
**The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.**
This is based on the definition of work in physics, which is calculated using the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where \(\theta\) is the angle between the force and the direction of movement. In this context, since the force is applied in the direction of the ball's travel, we can consider \(\cos(\theta)\) to be 1, simplifying the calculation to just force times distance.
**The work is determined by multiplying the force Derek exerts by the distance the ball travels in the direction of the force.**
This is based on the definition of work in physics, which is calculated using the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where \(\theta\) is the angle between the force and the direction of movement. In this context, since the force is applied in the direction of the ball's travel, we can consider \(\cos(\theta)\) to be 1, simplifying the calculation to just force times distance.