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Use the functions below. f(x)=3x−4 g(x)=3x+6 What is (f+g)(x) ? Enter the missing values. (1 point) (f+g)(x)=_^2+_ $$Asked by hudson
Use the functions below.
f(x)=x+3−−−−√−2
g(x)=x+3−−−−√
What is (f⋅g)(x)
?
Enter the missing values.
(1 point)
(f⋅g)(x)=x+
$$
f(x)=x+3−−−−√−2
g(x)=x+3−−−−√
What is (f⋅g)(x)
?
Enter the missing values.
(1 point)
(f⋅g)(x)=x+
$$
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find \((f \cdot g)(x)\), we need to multiply the two functions \(f(x)\) and \(g(x)\).
Given:
- \(f(x) = \sqrt{x + 3} - 2\)
- \(g(x) = \sqrt{x + 3}\)
Now, let's multiply these two functions:
\[
(f \cdot g)(x) = f(x) \cdot g(x) = (\sqrt{x + 3} - 2) \cdot \sqrt{x + 3}
\]
Next, we can use the distributive property to expand this multiplication:
\[
(f \cdot g)(x) = \sqrt{x + 3} \cdot \sqrt{x + 3} - 2 \cdot \sqrt{x + 3}
\]
This simplifies to:
\[
(f \cdot g)(x) = (x + 3) - 2\sqrt{x + 3}
\]
Thus, we can express this as:
\[
(f \cdot g)(x) = x + 3 - 2\sqrt{x + 3}
\]
Therefore, the final answer is:
\[
\boxed{x + 3 - 2\sqrt{x + 3}}
\]
If we need to fill in the specific parts as you mentioned, we should note:
- The answer for your completion is \(x + 3\), while the missing part regarding \(g(x)\) would be the term \(- 2\sqrt{x + 3}\).
Given:
- \(f(x) = \sqrt{x + 3} - 2\)
- \(g(x) = \sqrt{x + 3}\)
Now, let's multiply these two functions:
\[
(f \cdot g)(x) = f(x) \cdot g(x) = (\sqrt{x + 3} - 2) \cdot \sqrt{x + 3}
\]
Next, we can use the distributive property to expand this multiplication:
\[
(f \cdot g)(x) = \sqrt{x + 3} \cdot \sqrt{x + 3} - 2 \cdot \sqrt{x + 3}
\]
This simplifies to:
\[
(f \cdot g)(x) = (x + 3) - 2\sqrt{x + 3}
\]
Thus, we can express this as:
\[
(f \cdot g)(x) = x + 3 - 2\sqrt{x + 3}
\]
Therefore, the final answer is:
\[
\boxed{x + 3 - 2\sqrt{x + 3}}
\]
If we need to fill in the specific parts as you mentioned, we should note:
- The answer for your completion is \(x + 3\), while the missing part regarding \(g(x)\) would be the term \(- 2\sqrt{x + 3}\).
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