Question

Two tables were generated to compare the functions f(x) and g(x)=f(x)−1. Find the missing value in the table for the function g(x).(1 point)

| x | f(x) |
| 0 | 0 |
| -1 | 1 |
| 2 | 4 |

| x | g(x) |
| 0 | -1 |
|-1 | ? |
| 2 | 3 |

Answer 1

To find the missing value of \( g(x) \) in the second table, we can use the relationship defined by \( g(x) = f(x) - 1 \).

We can go through the provided \( f(x) \) values for the x-codes to find the corresponding \( g(x) \) values:

1. For \( x = 0 \):
\[
f(0) = 0 \implies g(0) = f(0) - 1 = 0 - 1 = -1
\]

2. For \( x = -1 \):
\[
f(-1) = 1 \implies g(-1) = f(-1) - 1 = 1 - 1 = 0
\]
This is the value we are looking for.

3. For \( x = 2 \):
\[
f(2) = 4 \implies g(2) = f(2) - 1 = 4 - 1 = 3
\]

Thus, the missing value in the table for \( g(-1) \) is \( 0 \).

So, the completed tables are:

| x | f(x) |
|---|-----|
| 0 | 0 |
| -1 | 1 |
| 2 | 4 |

| x | g(x) |
|---|-----|
| 0 | -1 |
| -1 | 0 |
| 2 | 3 |

The missing value for \( g(-1) \) is \( 0 \).