There are many ways you could solve this equation. We need to get v alone on one side, and a constant number alone on the other side. Since v is inside the parentheses on the left, we can use the distributive property to rewrite the equation without parentheses. Go for it. Distribute the

Question

2
1
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to 12v−8. You can think of this as (12v−8) is being multiplied by
2
1
​
.
2
1
​
(12v − 8) = 8v + 10
= 8v + 10

Answer 1

Let's solve the equation step by step.

You have the expression \( \frac{2}{1}(12v - 8) = 8v + 10 \).

1. Distribute \( \frac{2}{1} \) (which is 2) to both terms inside the parentheses: \[ 2(12v) - 2(8) = 24v - 16 \] So the equation now becomes: \[ 24v - 16 = 8v + 10 \]

2. Rearranging the equation: To get all the terms with \( v \) on one side and the constant terms on the other side, subtract \( 8v \) from both sides: \[ 24v - 8v - 16 = 10 \] This simplifies to: \[ 16v - 16 = 10 \]

3. Add 16 to both sides to isolate terms with \( v \): \[ 16v = 10 + 16 \] Which simplifies to: \[ 16v = 26 \]

4. Divide both sides by 16 to solve for \( v \): \[ v = \frac{26}{16} = \frac{13}{8} \]

Thus, the solution for \( v \) is: \[ v = \frac{13}{8} \]