Question
What current is produced with a voltage of 6.0 V and a resistance of 445 ohms?(1 point)
Responses
11.0 mA
11.0 mA
17.4 mA
17.4 mA
15.7 mA
15.7 mA
13.5 mA
Responses
11.0 mA
11.0 mA
17.4 mA
17.4 mA
15.7 mA
15.7 mA
13.5 mA
Answers
GPT-4o mini
To find the current produced with a voltage of 6.0 V and a resistance of 445 ohms, you can use Ohm's Law, which is given by the formula:
\[ I = \frac{V}{R} \]
where:
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).
Plugging in the values:
\[ I = \frac{6.0 \, \text{V}}{445 \, \Omega} \]
Calculating this:
\[ I = \frac{6.0}{445} \approx 0.01348 \, \text{A} \]
To convert amperes to milliamperes (mA), multiply by 1000:
\[ I \approx 0.01348 \, \text{A} \times 1000 \approx 13.48 \, \text{mA} \]
Rounding to two decimal places gives approximately 13.5 mA.
Thus, the correct response is:
**13.5 mA**
\[ I = \frac{V}{R} \]
where:
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).
Plugging in the values:
\[ I = \frac{6.0 \, \text{V}}{445 \, \Omega} \]
Calculating this:
\[ I = \frac{6.0}{445} \approx 0.01348 \, \text{A} \]
To convert amperes to milliamperes (mA), multiply by 1000:
\[ I \approx 0.01348 \, \text{A} \times 1000 \approx 13.48 \, \text{mA} \]
Rounding to two decimal places gives approximately 13.5 mA.
Thus, the correct response is:
**13.5 mA**