Question

Which function represents shifting h(x)=53x−−√+10
down 6 units?(1 point)
Responses

m(x)=53x−−√+4
m times x is equal to 5 square root of 3 x plus 4

p(x)=53x−−√+16
p times x is equal to 5 square root of 3 x plus 16

k(x)=53x−−√−6
k times x is equal to 5 square root of 3 x minus 6

g(x)=53x−6−−−−−√
g of x is equal to 5 square root of 3 x minus 6 end root

Answer 1

To shift the function \( h(x) = 5\sqrt{3x} + 10 \) down by 6 units, you need to subtract 6 from the entire function.

Starting with \( h(x) \):
\[
h(x) = 5\sqrt{3x} + 10
\]

To shift it down by 6:
\[
m(x) = h(x) - 6 = 5\sqrt{3x} + 10 - 6 = 5\sqrt{3x} + 4
\]

So the correct function that represents shifting \( h(x) \) down 6 units is:
\[
m(x) = 5\sqrt{3x} + 4
\]

Thus, the correct response is:
**m(x) = 5√(3x) + 4**.