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Solve the inequality and graph the solution. v+1 3 ≥ – 1 Plot the endpoints. Select an endpoint to change it from closed to ope...Asked by evergreen
Solve the inequality and graph the solution.
2(g+4)+10<6
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
2(g+4)+10<6
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
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Answered by
GPT-4o mini
To solve the inequality \( 2(g + 4) + 10 < 6 \), we will first simplify and isolate \( g \).
1. Distribute the \( 2 \):
\[
2g + 8 + 10 < 6
\]
2. Combine like terms:
\[
2g + 18 < 6
\]
3. Subtract \( 18 \) from both sides:
\[
2g < 6 - 18
\]
\[
2g < -12
\]
4. Divide both sides by \( 2 \):
\[
g < -6
\]
### Solution
The solution to the inequality is:
\[
g < -6
\]
### Graphing the Solution
To graph the solution \( g < -6 \):
1. **Identify the endpoints**: The endpoint is \( -6 \).
2. **Select an endpoint to change it from closed to open**: Since \( g < -6 \) does not include \( -6 \), we will represent it as an open circle at \( -6 \).
3. **Select the middle of the segment, ray, or line to delete it**: Since the solution is \( g < -6 \), we will shade to the left (in the negative direction) of \( -6 \).
### Final Graph
- Place an open circle at \( -6 \) to indicate that it is not included in the solution.
- Shade everything to the left of \( -6 \) to represent all values that are less than \( -6 \).
The graph will look like this:
\[
\text{---o-------------------}
-7 -6 -5
\]
Where "o" is an open circle representing \( -6 \) and the shading extends to all values left of \( -6 \).
1. Distribute the \( 2 \):
\[
2g + 8 + 10 < 6
\]
2. Combine like terms:
\[
2g + 18 < 6
\]
3. Subtract \( 18 \) from both sides:
\[
2g < 6 - 18
\]
\[
2g < -12
\]
4. Divide both sides by \( 2 \):
\[
g < -6
\]
### Solution
The solution to the inequality is:
\[
g < -6
\]
### Graphing the Solution
To graph the solution \( g < -6 \):
1. **Identify the endpoints**: The endpoint is \( -6 \).
2. **Select an endpoint to change it from closed to open**: Since \( g < -6 \) does not include \( -6 \), we will represent it as an open circle at \( -6 \).
3. **Select the middle of the segment, ray, or line to delete it**: Since the solution is \( g < -6 \), we will shade to the left (in the negative direction) of \( -6 \).
### Final Graph
- Place an open circle at \( -6 \) to indicate that it is not included in the solution.
- Shade everything to the left of \( -6 \) to represent all values that are less than \( -6 \).
The graph will look like this:
\[
\text{---o-------------------}
-7 -6 -5
\]
Where "o" is an open circle representing \( -6 \) and the shading extends to all values left of \( -6 \).
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