To solve the inequality \( 3(v + 2) < 9 \), we start by simplifying it.
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First, distribute the 3: \[ 3v + 6 < 9 \]
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Next, subtract 6 from both sides: \[ 3v < 3 \]
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Divide both sides by 3: \[ v < 1 \]
Now, we have the solution \( v < 1 \). This means that \( v \) can take any value less than 1.
Graph the Solution
To graph the solution:
- Endpoints: The endpoint here is 1.
- Since the inequality is \( v < 1 \) (not \( \leq \)), we use an open circle at 1 to indicate that 1 is not included in the solution.
- The line or ray will extend to the left of 1, indicating all values less than 1.
Representation of the Graph
- Draw a number line.
- Place an open circle at the point 1.
- Shade the line to the left of 1, indicating all numbers less than 1.
The final graph visually represents the solution \( v < 1 \) with the appropriate open endpoint and shaded area.