Volume of Spheres Practice

Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.(1 point)
mm3
the correct answer

2 answers

To find the volume of a sphere, you can use the formula:

\[ V = \frac{4}{3} \pi r^3 \]

where \( V \) is the volume, \( \pi \) is approximately 3.14, and \( r \) is the radius of the sphere.

Given:

  • \( r = 12 \) mm

Now, substituting the values into the formula:

\[ V = \frac{4}{3} \times 3.14 \times (12)^3 \]

First, calculate \( (12)^3 \):

\[ (12)^3 = 12 \times 12 \times 12 = 1728 \]

Now plug this into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

Now multiply \( 3.14 \times 1728 \):

\[ 3.14 \times 1728 \approx 5425.12 \]

Now, calculate \( \frac{4}{3} \times 5425.12 \):

\[ \frac{4}{3} \times 5425.12 \approx 7233.49 \]

Thus, the volume of the spherical chocolate truffle is approximately:

\[ \boxed{7233.49} \text{ mm}^3 \]

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