Volume of Spheres Practice

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Question
How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.(1 point)
mm3

1 answer

To find the volume of a sphere, you can use the formula:

\[ V = \frac{4}{3} \pi r^3 \]

Where:

  • \( V \) is the volume,
  • \( \pi \) is approximately 3.14,
  • \( r \) is the radius of the sphere.

Given that the radius of the chocolate truffle is \( r = 12 \) mm, we can substitute \( r \) into the formula:

\[ V = \frac{4}{3} \times 3.14 \times (12)^3 \]

First, calculate \( 12^3 \):

\[ 12^3 = 12 \times 12 \times 12 = 1728 \]

Now substitute \( 1728 \) back into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

Now perform the multiplication:

  1. Calculate \( \frac{4}{3} \times 1728 \):

\[ \frac{4 \times 1728}{3} = \frac{6912}{3} = 2304 \]

  1. Now multiply by \( 3.14 \):

\[ V = 2304 \times 3.14 = 7239.76 \]

Thus, the volume of the spherical chocolate truffle is approximately:

\[ \boxed{7239.76} , \text{mm}^3 \]