Question
The sides of a triangle measure 3 StartRoot 6 EndRoot, 2 StartRoot 24 EndRoot and 7 StartRoot 54 EndRoot. What is the perimeter of the triangle?
Answer options with 5 options
A.
31 StartRoot 2 EndRoot
B.
17 StartRoot 6 EndRoot
C.
24 StartRoot 21 EndRoot
D.
28 StartRoot 6 EndRoot
E.
12 StartRoot 84 EndRoot
Answer options with 5 options
A.
31 StartRoot 2 EndRoot
B.
17 StartRoot 6 EndRoot
C.
24 StartRoot 21 EndRoot
D.
28 StartRoot 6 EndRoot
E.
12 StartRoot 84 EndRoot
Answers
GPT-4o mini
To find the perimeter of the triangle, we need to first simplify each side:
1. **First side:**
\[
3\sqrt{6}
\]
2. **Second side:**
\[
2\sqrt{24} = 2\sqrt{4 \times 6} = 2 \cdot 2\sqrt{6} = 4\sqrt{6}
\]
3. **Third side:**
\[
7\sqrt{54} = 7\sqrt{9 \times 6} = 7 \cdot 3\sqrt{6} = 21\sqrt{6}
\]
Now, let's add all the sides together to find the perimeter:
\[
3\sqrt{6} + 4\sqrt{6} + 21\sqrt{6}
\]
Combining the terms:
\[
(3 + 4 + 21)\sqrt{6} = 28\sqrt{6}
\]
Thus, the perimeter of the triangle is:
\[
\boxed{28\sqrt{6}}
\]
Looking at the answer options, the correct choice is:
D. \(28 \sqrt{6}\)
1. **First side:**
\[
3\sqrt{6}
\]
2. **Second side:**
\[
2\sqrt{24} = 2\sqrt{4 \times 6} = 2 \cdot 2\sqrt{6} = 4\sqrt{6}
\]
3. **Third side:**
\[
7\sqrt{54} = 7\sqrt{9 \times 6} = 7 \cdot 3\sqrt{6} = 21\sqrt{6}
\]
Now, let's add all the sides together to find the perimeter:
\[
3\sqrt{6} + 4\sqrt{6} + 21\sqrt{6}
\]
Combining the terms:
\[
(3 + 4 + 21)\sqrt{6} = 28\sqrt{6}
\]
Thus, the perimeter of the triangle is:
\[
\boxed{28\sqrt{6}}
\]
Looking at the answer options, the correct choice is:
D. \(28 \sqrt{6}\)