Question
1. Determine what alleles will be found in all possible gametes that each parent can produce.
(out of four, B, B, b, b)
Possible gametes:
2. Enter the genotypes of the gametes produced by each parent on the top and left sides of the table.
3. Fill in the table by combining the gametes genotypes.
4. Determine the phenotypes and the genotypes of each offspring.
5. Calculate the percentage of each.
(out of four, B, B, b, b)
Possible gametes:
2. Enter the genotypes of the gametes produced by each parent on the top and left sides of the table.
3. Fill in the table by combining the gametes genotypes.
4. Determine the phenotypes and the genotypes of each offspring.
5. Calculate the percentage of each.
Answers
GPT-4o mini
Sure! Let’s go through the steps together based on the information provided.
### Step 1: Determine the Alleles from Each Parent
You have the alleles from one parent as: B, B, b, b.
Therefore, the possible gametes (alleles) from this parent will be:
- B
- B
- b
- b
For the sake of simplicity, we typically consider distinct gametes. Thus, the unique gametes from this parent are:
- B
- b
### Step 2: Enter Gametes Genotypes
Now, let's assume the second parent has the genotype "B, b" (let's say the second parent has the genotype Bb), as this information is required to create a complete punnett square.
Gametes from Parent 1 (Top):
- B
- b
Gametes from Parent 2 (Left):
- B
- b
### Step 3: Fill in the Table
Now, we combine the gametes in a 2x2 table:
| | **B** | **b** |
|-------|-------|-------|
| **B** | BB | Bb |
| **b** | Bb | bb |
### Step 4: Determine Phenotypes and Genotypes of Offspring
Now let's determine the genotypes and phenotypes of the offspring:
1. **BB**: Homozygous Dominant
- Genotype: BB
- Phenotype: Dominant trait expressed
2. **Bb**: Heterozygous
- Genotype: Bb
- Phenotype: Dominant trait expressed
3. **Bb**: Heterozygous (same as above)
- Genotype: Bb
- Phenotype: Dominant trait expressed
4. **bb**: Homozygous Recessive
- Genotype: bb
- Phenotype: Recessive trait expressed
### Step 5: Calculate Percentages of Each Genotype
Next, let's determine the percentages of each genotype:
- **BB**: 1 occurrence out of 4 (25%)
- **Bb**: 2 occurrences out of 4 (50%)
- **bb**: 1 occurrence out of 4 (25%)
### Summary of Results
- **Genotypes of Offspring**:
- BB: 1 (25%)
- Bb: 2 (50%)
- bb: 1 (25%)
- **Phenotypes of Offspring**:
- Dominant Trait: 3 out of 4 (75%)
- Recessive Trait: 1 out of 4 (25%)
### Conclusion
In summary, from the two parents represented, we expect:
- 25% of the offspring to have the genotype BB,
- 50% to have the genotype Bb,
- 25% to have the genotype bb,
- And the corresponding phenotypes would show 75% exhibiting the dominant trait and 25% exhibiting the recessive trait.
### Step 1: Determine the Alleles from Each Parent
You have the alleles from one parent as: B, B, b, b.
Therefore, the possible gametes (alleles) from this parent will be:
- B
- B
- b
- b
For the sake of simplicity, we typically consider distinct gametes. Thus, the unique gametes from this parent are:
- B
- b
### Step 2: Enter Gametes Genotypes
Now, let's assume the second parent has the genotype "B, b" (let's say the second parent has the genotype Bb), as this information is required to create a complete punnett square.
Gametes from Parent 1 (Top):
- B
- b
Gametes from Parent 2 (Left):
- B
- b
### Step 3: Fill in the Table
Now, we combine the gametes in a 2x2 table:
| | **B** | **b** |
|-------|-------|-------|
| **B** | BB | Bb |
| **b** | Bb | bb |
### Step 4: Determine Phenotypes and Genotypes of Offspring
Now let's determine the genotypes and phenotypes of the offspring:
1. **BB**: Homozygous Dominant
- Genotype: BB
- Phenotype: Dominant trait expressed
2. **Bb**: Heterozygous
- Genotype: Bb
- Phenotype: Dominant trait expressed
3. **Bb**: Heterozygous (same as above)
- Genotype: Bb
- Phenotype: Dominant trait expressed
4. **bb**: Homozygous Recessive
- Genotype: bb
- Phenotype: Recessive trait expressed
### Step 5: Calculate Percentages of Each Genotype
Next, let's determine the percentages of each genotype:
- **BB**: 1 occurrence out of 4 (25%)
- **Bb**: 2 occurrences out of 4 (50%)
- **bb**: 1 occurrence out of 4 (25%)
### Summary of Results
- **Genotypes of Offspring**:
- BB: 1 (25%)
- Bb: 2 (50%)
- bb: 1 (25%)
- **Phenotypes of Offspring**:
- Dominant Trait: 3 out of 4 (75%)
- Recessive Trait: 1 out of 4 (25%)
### Conclusion
In summary, from the two parents represented, we expect:
- 25% of the offspring to have the genotype BB,
- 50% to have the genotype Bb,
- 25% to have the genotype bb,
- And the corresponding phenotypes would show 75% exhibiting the dominant trait and 25% exhibiting the recessive trait.