To prove that \( \triangle ABC \cong \triangle QRS \) by the ASA (Angle-Side-Angle) Congruence Theorem, we need two angles and the side that is included between those angles to be congruent in both triangles.
Given that \( \angle B \cong \angle R \) (marked by double arcs) and \( BC \cong RS \) (both sides labeled as 3 inches), we need one more angle.
Thus, any of the following options could suffice in different scenarios, but the most direct response given the angle data is:
- \( \angle A \cong \angle Q \)
This choice provides the second angle needed to apply the ASA congruence theorem along with the side \( BC \).
So, the answer is:
∠A≅∠Q (angle A congruent to angle Q)