To find the number of bacteria in both petri dishes after \(x\) days, we can look at both the product and the sum of the functions \(f(x)\) and \(g(x)\).
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Sum of the functions: \[ (f+g)(x) = f(x) + g(x) = (3x + 2) + (3x + 5) = 6x + 7 \]
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Product of the functions: \[ (f \cdot g)(x) = f(x) \cdot g(x) = (3x + 2) \cdot (3x + 5) \] To find this, we can use the distributive property: \[ (3x + 2)(3x + 5) = 9x^2 + 15x + 6x + 10 = 9x^2 + 21x + 10 \]
Now let's summarize the results:
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The sum of the bacteria in the petri dishes after \(x\) days is: \[ (f+g)(x) = 6x + 7 \]
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The product of the bacteria in the petri dishes after \(x\) days is: \[ (f \cdot g)(x) = 9x^2 + 21x + 10 \]
Domain:
Since both functions represent the number of bacteria, the domain for \(x\) (the number of days) is non-negative: \[ \text{Domain: } x \geq 0 \]
Thus, the answers for the functions and the domain are:
- \( (f+g)(x) = 6x + 7 \) and the domain is \( x \geq 0 \).
- \( (f \cdot g)(x) = 9x^2 + 21x + 10 \) and the domain is also \( x \geq 0 \).
Final answer:
- Sum: \( (f+g)(x) = 6x + 7 \) and domain is \( x \geq 0 \).
- Product: \( (f \cdot g)(x) = 9x^2 + 21x + 10 \) and domain is \( x \geq 0 \).