Question

Graph has a slope of -4 and passes through the point (-4, 14) what’s the equation

Answer 1

To find the equation of a line with a slope of -4 that passes through the point (-4, 14), we can use the point-slope form of a linear equation, which is given by:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope, and \( (x_1, y_1) \) is the point the line passes through.

Here, \( m = -4 \), \( x_1 = -4 \), and \( y_1 = 14 \). Substituting these values into the point-slope formula gives:

\[
y - 14 = -4(x + 4)
\]

Now, we can simplify this equation:

\[
y - 14 = -4x - 16
\]

Adding 14 to both sides:

\[
y = -4x - 16 + 14
\]
\[
y = -4x - 2
\]

Thus, the equation of the line is:

\[
y = -4x - 2
\]