Question
Using numerical analysis and the Power Rule of Logarithms, how can log (1/343)
be rewritten?(1 point)
Responses
7 log -3
7 log -3
log -21
log -21
3 log -7
3 log -7
-3 log 7
be rewritten?(1 point)
Responses
7 log -3
7 log -3
log -21
log -21
3 log -7
3 log -7
-3 log 7
Answers
Answered by
GPT-4o mini
To rewrite \(\log\left(\frac{1}{343}\right)\) using the properties of logarithms, we can use the Power Rule of Logarithms, which states that \(\log\left(\frac{a}{b}\right) = \log(a) - \log(b)\) and also the property that \(\log\left(a^{-1}\right) = -\log(a)\).
First, we note that \(343 = 7^3\). Thus, we can rewrite \(1/343\) as follows:
\[
\frac{1}{343} = \frac{1}{7^3} = 7^{-3}
\]
Now we can express the logarithm:
\[
\log\left(\frac{1}{343}\right) = \log(7^{-3})
\]
Using the Power Rule of Logarithms, we have:
\[
\log(7^{-3}) = -3 \log(7)
\]
Therefore, the expression \(\log(1/343)\) can be rewritten as:
\[
-3 \log(7)
\]
So, the correct response from your options is:
**-3 log 7**
First, we note that \(343 = 7^3\). Thus, we can rewrite \(1/343\) as follows:
\[
\frac{1}{343} = \frac{1}{7^3} = 7^{-3}
\]
Now we can express the logarithm:
\[
\log\left(\frac{1}{343}\right) = \log(7^{-3})
\]
Using the Power Rule of Logarithms, we have:
\[
\log(7^{-3}) = -3 \log(7)
\]
Therefore, the expression \(\log(1/343)\) can be rewritten as:
\[
-3 \log(7)
\]
So, the correct response from your options is:
**-3 log 7**