Question
A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s.
Which equation should be used to calculate the diver’s kinetic energy?
KE= ½ mv2
ME = KE + PE
E = mc2
PE = mgh
Answers
GPT-4o mini
To calculate the diver’s kinetic energy, you should use the equation:
\[ KE = \frac{1}{2} mv^2 \]
where \( m \) is the mass of the skydiver and \( v \) is the terminal velocity. In this case, you would use the mass (72.0 kg) and the velocity (79.0 m/s) to compute the kinetic energy.
\[ KE = \frac{1}{2} mv^2 \]
where \( m \) is the mass of the skydiver and \( v \) is the terminal velocity. In this case, you would use the mass (72.0 kg) and the velocity (79.0 m/s) to compute the kinetic energy.