Solve the following inequality for x. x/4 + 7 ≤ 5/7

1 answer

To solve the inequality \( \frac{x}{4} + 7 \leq \frac{5}{7} \), follow these steps:

  1. Isolate the term with \( x \):

    \[ \frac{x}{4} \leq \frac{5}{7} - 7 \]

  2. Convert 7 to a fraction with a denominator of 7:

    \[ 7 = \frac{49}{7} \]

    Therefore,

    \[ \frac{5}{7} - 7 = \frac{5}{7} - \frac{49}{7} = \frac{5 - 49}{7} = \frac{-44}{7} \]

    Now the inequality is:

    \[ \frac{x}{4} \leq \frac{-44}{7} \]

  3. Multiply both sides by 4 to eliminate the fraction with \( x \). Remember to maintain the inequality direction (multiplying by a positive number):

    \[ x \leq 4 \cdot \frac{-44}{7} = \frac{-176}{7} \]

  4. State the solution:

    The solution to the inequality \( \frac{x}{4} + 7 \leq \frac{5}{7} \) is:

    \[ x \leq \frac{-176}{7} \]

This means that \( x \) can take any value up to and including \( \frac{-176}{7} \).