To find the equation of the trend line in slope-intercept form (y = mx + b), we first need to determine the slope (m) and the y-intercept (b).
Looking at the approximate points provided, we can identify two points to calculate the slope. Let's use the points \( (0, 9) \) and \( (10, 6.5) \).
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Calculate the slope (m): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6.5 - 9}{10 - 0} = \frac{-2.5}{10} = -0.25 \]
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Identify the y-intercept (b): From the point \( (0, 9) \), we can see that when \( x = 0 \), \( y = 9 \). So, the y-intercept \( b \) is 9.
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Write the equation: Now we can substitute the slope and y-intercept into the slope-intercept form: \[ y = -0.25x + 9 \]
Converting this to fraction format (since -0.25 = -\(\frac{1}{4}\)): \[ y = -\frac{1}{4}x + 9 \]
Based on the options given, the correct response is: y equals negative Start Fraction 1 over 4 End Fraction x plus 9.