I'm having trouble with question 2, please help
The velocity of an object in simple harmonic motion is given by v(t)= -(0.275 m/s)sin(23.0t + 2.00π), where t is in seconds.
1) What is the first time after t=0.00 s at which the velocity is -0.100 m/s?
2) What is the object's position at that time?
ANS 1) v(t)= -(0.275 m/s)sin(23.0t + 2.00π)
-.1 = -(0.275 m/s)sin(23.0t)
sin 23 t = .364
23 t = .372 rad
t = .0162 seconds
ANS 2) x = dv/dt = 0.275*cos(23t) = 0.275*cos(0.372rad) = 0.256 m which is incorrect for some reason!