Question
If a heat engine does 672 J of work from a heat reservoir of 1,600 J, then what is the efficiency of the
heat engine?
answers:
42%
92%
58%
38%
heat engine?
answers:
42%
92%
58%
38%
Answers
GPT-4o mini
The efficiency (\( \eta \)) of a heat engine is calculated using the formula:
\[
\eta = \frac{W}{Q_h}
\]
where \( W \) is the work done by the engine and \( Q_h \) is the heat extracted from the hot reservoir.
Given:
- Work done (\( W \)) = 672 J
- Heat from the reservoir (\( Q_h \)) = 1,600 J
Now, we can substitute the values:
\[
\eta = \frac{672 \, \text{J}}{1,600 \, \text{J}}
\]
Calculating this gives:
\[
\eta = 0.42
\]
To express this as a percentage, we multiply by 100:
\[
\eta = 0.42 \times 100 = 42\%
\]
Thus, the efficiency of the heat engine is **42%**.
\[
\eta = \frac{W}{Q_h}
\]
where \( W \) is the work done by the engine and \( Q_h \) is the heat extracted from the hot reservoir.
Given:
- Work done (\( W \)) = 672 J
- Heat from the reservoir (\( Q_h \)) = 1,600 J
Now, we can substitute the values:
\[
\eta = \frac{672 \, \text{J}}{1,600 \, \text{J}}
\]
Calculating this gives:
\[
\eta = 0.42
\]
To express this as a percentage, we multiply by 100:
\[
\eta = 0.42 \times 100 = 42\%
\]
Thus, the efficiency of the heat engine is **42%**.