To find the total mass of the reactants in the reaction:
\[ \text{FeCl}_3 + 3\text{H}_2\text{O} \]
We begin by calculating the mass of each reactant individually.
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Calculate the mass of FeCl₃:
- Iron (Fe): 1 × 56 amu = 56 amu
- Chlorine (Cl): 3 × 35 amu = 105 amu
- Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu
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Calculate the mass of 3 H₂O:
- Hydrogen (H): 2 × 1 amu = 2 amu (for each H₂O)
- Oxygen (O): 1 × 16 amu = 16 amu (for each H₂O)
- Total mass of one H₂O = 2 amu + 16 amu = 18 amu
- Total mass of 3 H₂O = 3 × 18 amu = 54 amu
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Total mass of the reactants:
- Total mass = mass of FeCl₃ + mass of 3 H₂O
- Total mass = 161 amu + 54 amu = 215 amu
Therefore, the total mass of the reactants is:
215 amu