To simplify the expression \((2^{-3} \cdot 9^{3})^{-4}/(2^{9} \cdot 9^{-10})\) using the properties of integer exponents, we will follow these steps:
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Apply the Negative Exponent Rule: When raising a product to a power, we can distribute the exponent to each factor.
\[ (2^{-3} \cdot 9^3)^{-4} = 2^{-3 \cdot -4} \cdot 9^{3 \cdot -4} = 2^{12} \cdot 9^{-12} \]
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Write out the whole expression: Now we rewrite the entire expression including the denominator:
\[ \frac{2^{12} \cdot 9^{-12}}{2^{9} \cdot 9^{-10}} \]
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Apply the Quotient Rule: The quotient rule states that for any bases \(a\), \(m\), and \(n\):
\[ \frac{a^m}{a^n} = a^{m-n} \]
Apply this rule to simplify each base:
- For \(2\):
\[ \frac{2^{12}}{2^{9}} = 2^{12 - 9} = 2^{3} \]
- For \(9\):
\[ \frac{9^{-12}}{9^{-10}} = 9^{-12 - (-10)} = 9^{-12 + 10} = 9^{-2} \]
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Combine the Results: Now we have:
\[ 2^{3} \cdot 9^{-2} \]
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Convert Expressions with Negative Exponents: To express everything with positive exponents:
\[ 2^{3} \cdot \frac{1}{9^2} = \frac{2^{3}}{9^{2}} \]
Thus, the equivalent expression with only positive exponents is:
\[ \frac{2^3}{9^2} \]
This is the final simplified expression.