Question

Question
Translate the figure HIJKL
3 units to the left. Which of the following would be the vertex of H ′
'?



(1 point)
Responses

(−7, 4)
(−7, 4)

(−6, 6)
(−6, 6)

(−1, −2)
(−1, −2)

(2, 4)
(2, 4)
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Answer 1

To translate the figure HIJKL 3 units to the left, you need to subtract 3 from the x-coordinate of each vertex.

Let’s assume the coordinates of vertex \( H \) are \( (x_H, y_H) \). After translating 3 units to the left, the new coordinate \( H' \) will be:

\[ H' = (x_H - 3, y_H) \]

However, since the original coordinates of point \( H \) are not provided, we cannot pinpoint the exact new location of \( H' \).

If the original coordinates of \( H \) were provided, you would simply subtract 3 from the x-coordinate of those coordinates to find \( H' \).

For example, if \( H \) was at \( (−4, 4) \):

\[ H' = (−4 - 3, 4) = (−7, 4) \]

You can apply this method with the actual coordinates of H once they are provided, or you can check the options if one corresponds to the transformation of \( H \).

From your choices:
- (−7, 4)
- (−6, 6)
- (−1, −2)
- (2, 4)

Only (−7, 4) is a point in the form of a 3-unit left translation of an original point, assuming the original point \( H \) is at (−4, 4).

Thus, if \( H \) is (−4, 4), then \( H' \) would be (−7, 4).

So, without knowing \( H \)'s original coordinates, I can conclude that if \( H \) is at \( (−4, 4) \), then the answer is:
**(−7, 4)**.