Asked by Ariel
                Which set of points are collinear?
a.)A(-1,5); B(2,6); C(4,7)
b.)A(0,0); B(1/2,3); C(1,5)
c.)A(-4,-2); B(0,-4); C(2,-5)
when i graph them they all look straight to me but the one I pick is
A(-1,5); B(2,6); C(4,7)
 
            
            
        a.)A(-1,5); B(2,6); C(4,7)
b.)A(0,0); B(1/2,3); C(1,5)
c.)A(-4,-2); B(0,-4); C(2,-5)
when i graph them they all look straight to me but the one I pick is
A(-1,5); B(2,6); C(4,7)
Answers
                    Answered by
            Reiny
            
    To be collinear, line segments have to be parallel, and a point must be common
for your choice
slopeAB=1/3, slope BC=1/2
so they are not parallel
b) slopeAB = 3/(1/2) = 6 , slope BC = 2/(1/2) = 4
not parallel
c) slopeAB = -2/4 = -1/2 , slope BC = -1/2
so the correct choice is c)
    
for your choice
slopeAB=1/3, slope BC=1/2
so they are not parallel
b) slopeAB = 3/(1/2) = 6 , slope BC = 2/(1/2) = 4
not parallel
c) slopeAB = -2/4 = -1/2 , slope BC = -1/2
so the correct choice is c)
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