Question
A force of 53 N is applied to an 11 kg
• * 1 poin
object. What is the object's acceleration?
583 N
4.8 m/s2
21 m/s2
• * 1 poin
object. What is the object's acceleration?
583 N
4.8 m/s2
21 m/s2
Answers
GPT-4o mini
To find the acceleration of the object, we can use Newton's second law of motion, which states that:
\[ F = m \cdot a \]
where:
- \( F \) is the force applied (in Newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in m/s²).
Given:
- \( F = 53 \, \text{N} \)
- \( m = 11 \, \text{kg} \)
We need to solve for \( a \):
\[ a = \frac{F}{m} \]
Substituting in the given values:
\[ a = \frac{53 \, \text{N}}{11 \, \text{kg}} \]
Calculating this gives:
\[ a \approx 4.818 \, \text{m/s}^2 \]
Rounding to one decimal place, the acceleration is approximately:
\[ a \approx 4.8 \, \text{m/s}^2 \]
Therefore, the correct answer is **4.8 m/s²**.
\[ F = m \cdot a \]
where:
- \( F \) is the force applied (in Newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in m/s²).
Given:
- \( F = 53 \, \text{N} \)
- \( m = 11 \, \text{kg} \)
We need to solve for \( a \):
\[ a = \frac{F}{m} \]
Substituting in the given values:
\[ a = \frac{53 \, \text{N}}{11 \, \text{kg}} \]
Calculating this gives:
\[ a \approx 4.818 \, \text{m/s}^2 \]
Rounding to one decimal place, the acceleration is approximately:
\[ a \approx 4.8 \, \text{m/s}^2 \]
Therefore, the correct answer is **4.8 m/s²**.