Question

Subtract, answer as a mixed number in simplest form.
2 3/4 - 1 1/6
[__] [__]/[__]

Answer 1

To subtract the mixed numbers \(2 \frac{3}{4}\) and \(1 \frac{1}{6}\), follow these steps:

1. **Convert mixed numbers to improper fractions:**

- For \(2 \frac{3}{4}\):
\[
2 \frac{3}{4} = \left(2 \times 4 + 3\right) / 4 = \frac{8 + 3}{4} = \frac{11}{4}
\]

- For \(1 \frac{1}{6}\):
\[
1 \frac{1}{6} = \left(1 \times 6 + 1\right) / 6 = \frac{6 + 1}{6} = \frac{7}{6}
\]

2. **Now, subtract the two improper fractions:**
\[
\frac{11}{4} - \frac{7}{6}
\ \text{To perform the subtraction, we need a common denominator.}
\]
- The least common multiple of 4 and 6 is 12.

- Convert \(\frac{11}{4}\) to have a denominator of 12:
\[
\frac{11}{4} = \frac{11 \times 3}{4 \times 3} = \frac{33}{12}
\]

- Convert \(\frac{7}{6}\) to have a denominator of 12:
\[
\frac{7}{6} = \frac{7 \times 2}{6 \times 2} = \frac{14}{12}
\]

3. **Now perform the subtraction:**
\[
\frac{33}{12} - \frac{14}{12} = \frac{33 - 14}{12} = \frac{19}{12}
\]

4. **Convert the improper fraction \(\frac{19}{12}\) back to a mixed number:**
- Divide 19 by 12 to find the whole number part:
\[
19 \div 12 = 1 \quad \text{(with a remainder of 7)}
\]

- This gives us:
\[
1 \quad \text{(whole part)} + \frac{7}{12} \quad \text{(fractional part)} = 1 \frac{7}{12}
\]

5. **Final answer:**
\[
1 \frac{7}{12}
\]

So, in the format you asked for, the answer is \([1] [7]/[12]\).

Answer 2

That's pretty wrong, try again.