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Original Question
write an expression that is equivalent to 1/4a - 3. 1/4a - 3 = ___ (a - ___)Question
write an expression that is equivalent to 1/4a - 3.
1/4a - 3 =__ (a - __)
1/4a - 3 =__ (a - __)
Answers
Answered by
GPT-4o mini
To rewrite the expression \( \frac{1}{4}a - 3 \) in the form \( (a - \_\_) \), we will factor out \( \frac{1}{4} \).
Start with the expression:
\[
\frac{1}{4}a - 3
\]
We want to factor out \( \frac{1}{4} \):
\[
\frac{1}{4}(a - \_\_)
\]
To find what goes in the blank, we need to set the inside of the parentheses equal to the original expression. We can rewrite \( -3 \) in a form that involves \( \frac{1}{4} \):
\[
-3 = -\frac{12}{4}
\]
So, the expression can be rewritten as:
\[
\frac{1}{4}(a - 12)
\]
Thus, the final equivalent expression is:
\[
\frac{1}{4}a - 3 = \frac{1}{4}(a - 12)
\]
In the format given, it can be stated as:
\[
\frac{1}{4}a - 3 = \frac{1}{4}(a - 12)
\]
So, filling in the blanks:
\[
\frac{1}{4}a - 3 = (a - 12)
\]
However, remember that \( \frac{1}{4} \) is factored out, so the expression we derived is correct as it stands. The final part you intended with \( \_\_ \) would be filled by noting that 12 is needed to balance the equation wrt the original expression's constants.
Start with the expression:
\[
\frac{1}{4}a - 3
\]
We want to factor out \( \frac{1}{4} \):
\[
\frac{1}{4}(a - \_\_)
\]
To find what goes in the blank, we need to set the inside of the parentheses equal to the original expression. We can rewrite \( -3 \) in a form that involves \( \frac{1}{4} \):
\[
-3 = -\frac{12}{4}
\]
So, the expression can be rewritten as:
\[
\frac{1}{4}(a - 12)
\]
Thus, the final equivalent expression is:
\[
\frac{1}{4}a - 3 = \frac{1}{4}(a - 12)
\]
In the format given, it can be stated as:
\[
\frac{1}{4}a - 3 = \frac{1}{4}(a - 12)
\]
So, filling in the blanks:
\[
\frac{1}{4}a - 3 = (a - 12)
\]
However, remember that \( \frac{1}{4} \) is factored out, so the expression we derived is correct as it stands. The final part you intended with \( \_\_ \) would be filled by noting that 12 is needed to balance the equation wrt the original expression's constants.
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