Question

Start by finding the value of x. Solve on paper, then enter your answers on Zearn.
y= 5x+6
x= 23−2y
x =

y = ?

Answer 1

To solve the system of equations given:

1. \( y = 5x + 6 \) (Equation 1)
2. \( x = 23 - 2y \) (Equation 2)

We can start by substituting Equation 1 into Equation 2.

1. From Equation 1, we have \( y = 5x + 6 \).
2. Substitute this expression for \( y \) into Equation 2:

\[
x = 23 - 2(5x + 6)
\]

Now, simplify the equation:

\[
x = 23 - 10x - 12
\]

Combine like terms:

\[
x = 11 - 10x
\]

Next, add \( 10x \) to both sides:

\[
x + 10x = 11
\]

This simplifies to:

\[
11x = 11
\]

Now divide both sides by 11:

\[
x = 1
\]

Now that we have the value of \( x \), we can substitute it back into Equation 1 to find \( y \):

\[
y = 5(1) + 6
\]
\[
y = 5 + 6 = 11
\]

So, the values are:

\[
x = 1
\]
\[
y = 11
\]

Feel free to enter these values into Zearn!