Question

Find the midpoint
(-15,12) (3,-8)

Answer 1

To find the midpoint of two points \((x_1, y_1)\) and \((x_2, y_2)\), you can use the midpoint formula:

\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

For the points \((-15, 12)\) and \((3, -8)\):

- \(x_1 = -15\)
- \(y_1 = 12\)
- \(x_2 = 3\)
- \(y_2 = -8\)

Now, plug these values into the midpoint formula:

\[
\text{Midpoint} = \left( \frac{-15 + 3}{2}, \frac{12 + (-8)}{2} \right)
\]

Calculating the x-coordinate:

\[
\frac{-15 + 3}{2} = \frac{-12}{2} = -6
\]

Calculating the y-coordinate:

\[
\frac{12 - 8}{2} = \frac{4}{2} = 2
\]

Therefore, the midpoint is:

\[
\text{Midpoint} = (-6, 2)
\]