To compare the functions \( f(x) = 2\sqrt{x} \) and \( g(x) = \sqrt[3]{2x} \), we need to analyze their domains, behavior, and points on the graphs.
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Domains:
- For \( f(x) = 2\sqrt{x} \), the function is defined for \( x \geq 0 \) because square roots of negative numbers are not defined in the real number system.
- For \( g(x) = \sqrt[3]{2x} \), the function is defined for all \( x \) because cube roots are defined for all real numbers.
This means that the two functions do indeed have different domains.
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Behavior:
- \( f(x) = 2\sqrt{x} \) is increasing for \( x \geq 0 \).
- \( g(x) = \sqrt[3]{2x} \) is also increasing for all real \( x \).
Thus, they are not both decreasing on their domains.
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Points:
- For \( f(x) \):
- \( f(-1) \) is undefined.
- \( f(0) = 0 \)
- \( f(1) = 2 \)
- For \( g(x) \):
- \( g(-1) = \sqrt[3]{-2} \) (which is a negative value, around -1.26)
- \( g(0) = 0 \)
- \( g(1) = \sqrt[3]{2} \) (which is approximately 1.26)
Therefore, both graphs do not pass through the same points \( (-1, -1) \), \( (0, 0) \), and \( (1, 1) \).
- For \( f(x) \):
Based on the analysis, the correct statement is:
The graphs have different domains.