37.
Classify ABC by its angles if m<A= x m<B=2x and m<C= 3x
obtuse
right
isosceles
equilateral
3 answers
obtuse
8.
Which is the equation of the line that contains points (0, 5) and (5, 8)?
Which is the equation of the line that contains points (0, 5) and (5, 8)?
To find the equation of a line passing through two points, we can use the point-slope formula:
The point-slope formula is: y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
Given points are (0, 5) and (5, 8). So, we can use the first point to calculate the equation.
Let's use the first point (0, 5):
To find the slope (m) of the line:
m = (y2 - y1) / (x2 - x1) = (8 - 5) / (5 - 0) = 3 / 5
Now we have the slope m = 3/5 and a point (0, 5).
Now use the point-slope formula to find the equation:
y - 5 = (3/5)(x - 0)
y - 5 = 3/5x
5y - 25 = 3x
3x - 5y + 25 = 0
Therefore, the equation of the line passing through points (0, 5) and (5, 8) is 3x - 5y + 25 = 0.
The point-slope formula is: y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
Given points are (0, 5) and (5, 8). So, we can use the first point to calculate the equation.
Let's use the first point (0, 5):
To find the slope (m) of the line:
m = (y2 - y1) / (x2 - x1) = (8 - 5) / (5 - 0) = 3 / 5
Now we have the slope m = 3/5 and a point (0, 5).
Now use the point-slope formula to find the equation:
y - 5 = (3/5)(x - 0)
y - 5 = 3/5x
5y - 25 = 3x
3x - 5y + 25 = 0
Therefore, the equation of the line passing through points (0, 5) and (5, 8) is 3x - 5y + 25 = 0.