Simplify the expression.

fraction with negative 5 times the quantity 3 minus the cube root of 27 times 2 end quantity as the numerator and 3 as the denominator

six fifths
5
negative six fifths
−5

1 answer

Let's simplify the expression step-by-step.

We start with the expression:

\[ \frac{-5(3 - \sqrt[3]{27} \cdot 2)}{3} \]

First, we can compute the cube root of \(27\):

\[ \sqrt[3]{27} = 3 \]

Now substitute this value back into the expression:

\[ \frac{-5(3 - 3 \cdot 2)}{3} \]

Next, simplify \(3 \cdot 2\):

\[ 3 \cdot 2 = 6 \]

Now substitute that into the expression:

\[ \frac{-5(3 - 6)}{3} \]

This simplifies to:

\[ \frac{-5(-3)}{3} \]

Now, simplify \(-5(-3)\):

\[ -5 \cdot -3 = 15 \]

We are left with:

\[ \frac{15}{3} \]

Finally, divide:

\[ \frac{15}{3} = 5 \]

Thus, the simplified expression is:

\[ \boxed{5} \]