Question

Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother.
Charlie has $27. How much can he spend on each sandwich if they are all the same price?
The inequality representing how much Charlie can spend is
choose your answer...
3x + 6 < 27
6x + 3 ≥27
3x+ 6 ≥27
6x+ 3≤27
Charlie can spend ________

Answer 1

Let's break down the problem:

1. Charlie is ordering 6 sandwiches (let's call the price of each sandwich \( x \)).
2. He is also ordering a $3 kid's meal.
3. Charlie has a total of $27 to spend.

The total cost of the sandwiches plus the kid's meal can be expressed as:

\[ 6x + 3 \]

This total needs to be less than or equal to Charlie's budget of $27. Therefore, the inequality can be written as:

\[ 6x + 3 ≤ 27 \]

Now we can simplify the inequality:

\[ 6x + 3 ≤ 27 \]
Subtract 3 from both sides:

\[ 6x ≤ 24 \]
Now divide both sides by 6:

\[ x ≤ 4 \]

This means that Charlie can spend a maximum of $4 on each sandwich.

So, to answer your question:

The correct inequality is:
**6x + 3 ≤ 27**

Charlie can spend **up to $4** on each sandwich.