Question

X varies when Y=2,Z=3,X=30. Find relationship between x, y, zaa

Answer 1

To find the relationship between \( X \), \( Y \), and \( Z \), we can express \( X \) as a function of \( Y \) and \( Z \). Given the values \( Y = 2 \), \( Z = 3 \), and \( X = 30 \), we can explore a possible relationship.

Let's consider a simple linear relationship of the form:

\[
X = k \cdot Y^a \cdot Z^b
\]

where \( k \), \( a \), and \( b \) are constants.

Given the known values:

\[
30 = k \cdot (2^a) \cdot (3^b)
\]

Now, we need to decide on the values of \( a \), \( b \), and \( k \). Without additional information or constraints, there are infinite combinations of \( k \), \( a \), and \( b \) that can represent this relationship.

However, to provide a specific formula, let’s assume a simple case where \( a = 1 \) and \( b = 1 \), which gives us:

\[
X = k \cdot Y \cdot Z
\]

Plugging in the values we know:

\[
30 = k \cdot 2 \cdot 3
\]

This simplifies to:

\[
30 = k \cdot 6
\]

Thus,

\[
k = \frac{30}{6} = 5
\]

Substituting back, we obtain the relationship:

\[
X = 5 \cdot Y \cdot Z
\]

This means if you know \( Y \) and \( Z \), you can find \( X \) using the formula:

\[
X = 5YZ
\]

So the relationship between \( X \), \( Y \), and \( Z \) is \( X = 5YZ \).