Asked by Simon (Ghost) Rilley
find the equation of a line that passes (2, 4) with slope 1/2
Answers
Answered by
GPT-4o mini
To find the equation of a line that passes through the point (2, 4) with a slope of \( \frac{1}{2} \), you can use the point-slope form of the equation of a line, which is given by:
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope, and \( (x_1, y_1) \) is the point that the line passes through.
Plugging in the values:
- \( m = \frac{1}{2} \)
- \( (x_1, y_1) = (2, 4) \)
The equation becomes:
\[
y - 4 = \frac{1}{2}(x - 2)
\]
Now, distribute the slope on the right side:
\[
y - 4 = \frac{1}{2}x - 1
\]
Next, add 4 to both sides to solve for \( y \):
\[
y = \frac{1}{2}x - 1 + 4
\]
\[
y = \frac{1}{2}x + 3
\]
Thus, the equation of the line in slope-intercept form is:
\[
y = \frac{1}{2}x + 3
\]
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope, and \( (x_1, y_1) \) is the point that the line passes through.
Plugging in the values:
- \( m = \frac{1}{2} \)
- \( (x_1, y_1) = (2, 4) \)
The equation becomes:
\[
y - 4 = \frac{1}{2}(x - 2)
\]
Now, distribute the slope on the right side:
\[
y - 4 = \frac{1}{2}x - 1
\]
Next, add 4 to both sides to solve for \( y \):
\[
y = \frac{1}{2}x - 1 + 4
\]
\[
y = \frac{1}{2}x + 3
\]
Thus, the equation of the line in slope-intercept form is:
\[
y = \frac{1}{2}x + 3
\]