To calculate \((f+g+h)(x)\), we will first define each function explicitly and then sum them:
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Define the functions:
- \( f(x) = \sqrt{x - 5} + 2 \)
- \( g(x) = -2\sqrt{x - 5} - 7 \)
- \( h(x) = -\sqrt{x - 5} \)
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Sum the functions: \[ (f + g + h)(x) = f(x) + g(x) + h(x) \] \[ = (\sqrt{x - 5} + 2) + (-2\sqrt{x - 5} - 7) + (-\sqrt{x - 5}) \] Combining like terms: \[ = \sqrt{x - 5} - 2\sqrt{x - 5} - \sqrt{x - 5} + 2 - 7 \] The square root terms combine to: \[ = (1 - 2 - 1)\sqrt{x - 5} + (2 - 7) = -2\sqrt{x - 5} - 5 \]
Thus, we have: \[ (f + g + h)(x) = -2\sqrt{x - 5} - 5 \]
- Determine the domain: The domain of each function involves the term \(\sqrt{x - 5}\). The expression under the square root must be non-negative: \[ x - 5 \geq 0 \ x \geq 5 \]
Therefore, the domain of \( (f + g + h)(x) \) is \( x \geq 5 \).
Conclusion:
- \((f + g + h)(x) = -2\sqrt{x - 5} - 5\)
- The domain of \((f + g + h)(x)\) is \( x \geq 5 \).
The correct response based on your options would be: \[ (f + g + h)(x) = -2\sqrt{x - 5} - 5 \text{ and the domain of } (f + g + h)(x) \text{ is } x \geq 5. \]