Asked by Naila
NaCl (aq) + NH3(aq) + H2O(l) + CO2(s) --> NH4Cl(aq) + NaHCO3(s)
because they are relatively cheap, sodium chloride and water are typically present in excess. what is the expected yield of NaHCO3 when one performs such a synthesis using 10.0 g of ammonia and 15.0 g of dry ice - CO2(s), with an excess of NaCl and water-H20?
because they are relatively cheap, sodium chloride and water are typically present in excess. what is the expected yield of NaHCO3 when one performs such a synthesis using 10.0 g of ammonia and 15.0 g of dry ice - CO2(s), with an excess of NaCl and water-H20?
Answers
Answered by
DrBob222
Convert 10.0 g NH3 to moles. moles = grams/molar mass.
Convert 15.0 g CO2 to moles.
Now convert moles NH3 to moles product and convert moles CO2 to moles product. Determine the limiting reagent. Finally, convert moles of the product to grams product.
Convert 15.0 g CO2 to moles.
Now convert moles NH3 to moles product and convert moles CO2 to moles product. Determine the limiting reagent. Finally, convert moles of the product to grams product.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.