Solve for a.

a–18+29a<

38 or
a–89
5


4
Write your answer as a compound inequality with integers, proper fractions, and improper fractions in simplest form.

1 answer

To solve the inequalities \( a - 18 + 29a < -38 \) and \( a - \frac{89}{5} \geq -4 \), we will deal with each inequality separately.

1. Solving the first inequality:

\[ a - 18 + 29a < -38 \] Combine like terms: \[ 30a - 18 < -38 \] Add 18 to both sides: \[ 30a < -38 + 18 \] \[ 30a < -20 \] Divide both sides by 30: \[ a < -\frac{20}{30} \] Simplify: \[ a < -\frac{2}{3} \]

2. Solving the second inequality:

\[ a - \frac{89}{5} \geq -4 \] Add \(\frac{89}{5}\) to both sides: \[ a \geq -4 + \frac{89}{5} \] Convert \(-4\) to a fraction with a denominator of 5: \[ -4 = -\frac{20}{5} \] Now combine the fractions: \[ a \geq -\frac{20}{5} + \frac{89}{5} \] \[ a \geq \frac{89 - 20}{5} \] \[ a \geq \frac{69}{5} \]

Combine the results:

We have two parts:

  1. \( a < -\frac{2}{3} \)
  2. \( a \geq \frac{69}{5} \)

Final answer:

The solution set is: \[ \boxed{a < -\frac{2}{3} \text{ or } a \geq \frac{69}{5}} \]