To solve the system of equations given by:
- \(y = 12x + 2\)
- \(y = 2x - 1\)
we will set the two equations equal to each other to find the intersection point, which is the solution to the system:
\[ 12x + 2 = 2x - 1 \]
Now, we'll solve for \(x\):
-
Move \(2x\) to the left side: \[ 12x - 2x + 2 = -1 \] which simplifies to: \[ 10x + 2 = -1 \]
-
Next, subtract \(2\) from both sides: \[ 10x = -3 \]
-
Now, divide by \(10\): \[ x = -\frac{3}{10} = -0.3 \]
Now that we have the \(x\)-coordinate, we can substitute \(x = -0.3\) back into either of the original equations to find the \(y\)-coordinate. We'll use the second equation:
\[ y = 2(-0.3) - 1 = -0.6 - 1 = -1.6 \]
So, the apparent solution to the system of equations is: \[ (x, y) = \left(-0.3, -1.6\right) \]
Graphing the System of Equations
-
Graph the First Equation \(y = 12x + 2\):
- When \(x = 0\): \(y = 2\)
- When \(x = 1\): \(y = 14\)
- When \(x = -1\): \(y = -10\)
-
Graph the Second Equation \(y = 2x - 1\):
- When \(x = 0\): \(y = -1\)
- When \(x = 1\): \(y = 1\)
- When \(x = -1\): \(y = -3\)
Plotting Points
After plotting both lines based on the coordinates calculated:
- The line for \(y = 12x + 2\) is steep, and crosses the y-axis at (0,2).
- The line for \(y = 2x - 1\) rises more gradually and crosses the y-axis at (0,-1).
To locate the apparent solution on the graph:
- Plot the point \((-0.3, -1.6)\).
This point lies somewhere between the intersections of the two lines, where they intersect at the calculated coordinates.
Final Step
Ensure to highlight the point \((-0.3, -1.6)\) clearly while graphing. If you're using digital drawing or graphing software, you can enable the line and point tools to accomplish this.