Let's define the number of dimes Kecia has as \( d \). Since she has 3 more nickels than dimes, the number of nickels can be expressed as \( n = d + 3 \).
The total value of the coins can be expressed in cents. Dimes are worth 10 cents and nickels are worth 5 cents. Therefore, we can write the equation for the total value as follows:
\[ 10d + 5n = 150 \]
Substituting \( n = d + 3 \) into the value equation gives:
\[ 10d + 5(d + 3) = 150 \]
Simplifying this, we get:
\[ 10d + 5d + 15 = 150 \]
Combining like terms:
\[ 15d + 15 = 150 \]
Subtracting 15 from both sides:
\[ 15d = 135 \]
Dividing both sides by 15:
\[ d = 9 \]
Now, substituting back to find the number of nickels:
\[ n = d + 3 = 9 + 3 = 12 \]
So Kecia has 12 nickels and 9 dimes.
Thus, the completed statement is:
Kecia has 12 nickels and 9 dimes.
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