Question

A sandwich costs $0.75 more than a container of milk. A customer buys 4 sandwiches and 4 containers of milk. The customer pays $7.00.

What is the cost of a sandwich?

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1 answer

Let \( x \) be the cost of a container of milk. Then the cost of a sandwich is \( x + 0.75 \).

The customer buys 4 sandwiches and 4 containers of milk, so the total cost can be expressed as:

\[ 4(x + 0.75) + 4x = 7.00 \]

Expanding this gives:

\[ 4x + 3.00 + 4x = 7.00 \]

Combining like terms results in:

\[ 8x + 3.00 = 7.00 \]

Next, we subtract \( 3.00 \) from both sides:

\[ 8x = 4.00 \]

Now, divide by \( 8 \):

\[ x = 0.50 \]

The cost of a container of milk is \( 0.50 \). Therefore, the cost of a sandwich is:

\[ x + 0.75 = 0.50 + 0.75 = 1.25 \]

Thus, the cost of a sandwich is:

\[ \boxed{1.25} \]