Question

Question
A sandwich costs $0.75 more than a container of milk. A customer buys 4 sandwiches and 4 containers of milk. The customer pays $7.00.

What is the cost of a sandwich?

Enter your answer in the box.

$

Answer 1

Let \( x \) be the cost of a container of milk. Then the cost of a sandwich is \( x + 0.75 \).

The customer buys 4 sandwiches and 4 containers of milk, so the total cost can be expressed as:

\[
4(x + 0.75) + 4x = 7.00
\]

Expanding this gives:

\[
4x + 3.00 + 4x = 7.00
\]

Combining like terms results in:

\[
8x + 3.00 = 7.00
\]

Next, we subtract \( 3.00 \) from both sides:

\[
8x = 4.00
\]

Now, divide by \( 8 \):

\[
x = 0.50
\]

The cost of a container of milk is \( 0.50 \). Therefore, the cost of a sandwich is:

\[
x + 0.75 = 0.50 + 0.75 = 1.25
\]

Thus, the cost of a sandwich is:

\[
\boxed{1.25}
\]