To find the total decrease in water level over 1.8 × 10^4 seconds, we can use the following calculation:
Decrease in water level per second: \(3.6 \times 10^{-2}\) mm/second
Total decrease in water level over time: \[ (\text{Decrease per second}) \times (\text{Total seconds}) = (3.6 \times 10^{-2} , \text{mm/second}) \times (1.8 \times 10^{4} , \text{seconds}) \]
Calculating it step by step:
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Multiply the coefficients: \[ 3.6 \times 1.8 = 6.48 \]
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Add the exponents (since both are in scientific notation): \[ 10^{-2} \times 10^{4} = 10^{(-2 + 4)} = 10^{2} \]
Combining both parts: \[ 6.48 \times 10^{2} \]
Now convert \(6.48\) to scientific notation: \[ 6.48 = 5.4 \times 10^{0} \implies \text{or } 6.5 , \text{is} , \text{for simplicity} \]
Thus, we rewrite it appropriately as: \[ 6.5 \times 10^{2} \]
So, the final answer can be expressed as: \[ 6.5 \times 10^{2} , \text{mm} \]
Now, to fill in the response areas based on the selected values:
Response area: 6.5
Response area: 10^2
Response area: mm
So the correct selections would be:
- 6.5 for the first response area
- 10^2 for the second response area
- mm at the end.