Let's solve each inequality separately.
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For the first inequality: \[ 3w + 2 \geq 8 \] Subtract 2 from both sides: \[ 3w \geq 6 \] Divide both sides by 3: \[ w \geq 2 \]
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For the second inequality: \[ \frac{3w + 7}{2} < 5 \] Multiply both sides by 2 (since 2 is positive, the inequality sign stays the same): \[ 3w + 7 < 10 \] Subtract 7 from both sides: \[ 3w < 3 \] Divide both sides by 3: \[ w < 1 \]
Now we combine the solutions from both inequalities:
- The first inequality gives us \( w \geq 2 \).
- The second inequality gives us \( w < 1 \).
Expressing this as a compound inequality, we get:
\[ w < 1 \quad \text{or} \quad w \geq 2 \]
Thus, the final solution is: \[ \boxed{(-\infty, 1) \cup [2, \infty)} \]