What is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

Question 5 options:

0.21 m/s2

4.74 m/s2

21.09 m/s2

216.00 m/s2

1 answer

To find the acceleration of an object, you can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

Where:

  • \( F \) is the force applied (in newtons),
  • \( m \) is the mass of the object (in kilograms),
  • \( a \) is the acceleration (in meters per second squared).

You can rearrange the formula to solve for acceleration:

\[ a = \frac{F}{m} \]

Given:

  • \( F = 6.75 , \text{N} \)
  • \( m = 32 , \text{kg} \)

Now, substitute the values into the equation:

\[ a = \frac{6.75 , \text{N}}{32 , \text{kg}} \]

\[ a = 0.2109375 , \text{m/s}^2 \]

Rounding this to two decimal places gives:

\[ a \approx 0.21 , \text{m/s}^2 \]

So the correct answer is:

0.21 m/s²