Question

What is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

Question 5 options:

0.21 m/s2


4.74 m/s2


21.09 m/s2


216.00 m/s2

Answer 1

To find the acceleration of an object, you can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

Where:
- \( F \) is the force applied (in newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in meters per second squared).

You can rearrange the formula to solve for acceleration:

\[ a = \frac{F}{m} \]

Given:
- \( F = 6.75 \, \text{N} \)
- \( m = 32 \, \text{kg} \)

Now, substitute the values into the equation:

\[ a = \frac{6.75 \, \text{N}}{32 \, \text{kg}} \]

\[ a = 0.2109375 \, \text{m/s}^2 \]

Rounding this to two decimal places gives:

\[ a \approx 0.21 \, \text{m/s}^2 \]

So the correct answer is:

**0.21 m/s²**