Question

Evaluate the expression for x = 6, y = –13, and z = 1. Simplify your answer.

–6
xz2 + x + y
=

Answer 1

To evaluate the expression \(-6 \cdot (xz^2 + x + y)\) for \(x = 6\), \(y = -13\), and \(z = 1\), we will first substitute the values of \(x\), \(y\), and \(z\) into the expression.

1. Calculate \(z^2\):
\[
z^2 = 1^2 = 1
\]

2. Calculate \(xz^2\):
\[
xz^2 = 6 \cdot 1 = 6
\]

3. Now substitute \(x\) and \(y\) into the expression \(xz^2 + x + y\):
\[
xz^2 + x + y = 6 + 6 + (-13)
\]
\[
= 6 + 6 - 13 = 12 - 13 = -1
\]

4. Now substitute back into the original expression:
\[
-6 \cdot (xz^2 + x + y) = -6 \cdot (-1) = 6
\]

Thus, the simplified answer is:
\[
\boxed{6}
\]