Question

If a heat engine is operating between two temperatures (QH>QC
), what is the maximum efficiency attainable?(1 point)
Responses

QC−QH
upper Q subscript upper C baseline minus upper Q subscript upper H baseline

1−QHQC
1 minus Start Fraction upper Q subscript upper H baseline over upper Q subscript upper C baseline End Fraction

1−QCQH
1 minus Start Fraction upper Q subscript upper C baseline over upper Q subscript upper H baseline End Fraction

QH−QC

Answer 1

The maximum efficiency of a heat engine operating between two temperatures is given by the Carnot efficiency formula, which is represented as:

\[
\text{Efficiency} = 1 - \frac{Q_C}{Q_H}
\]

where \(Q_H\) is the heat absorbed from the hot reservoir and \(Q_C\) is the heat expelled to the cold reservoir.

Thus, the correct response from your options is:

**1−(QC / QH)**

This corresponds to the expression:

\[
1 - \frac{Q_C}{Q_H}
\]

So the answer is:

**1−QC/QH**